The Flame of the Yukon (1917)

The Flame, a dance hall girl who rules the Midas Café, is notorious from Nome to Dawson. She meets her match in a youth named George Fowler, whose good looks and raw nerve compel her to grubstake him and go straight while awaiting his return from the gold fields. One day, a young girl and her baby arrive at the camp, looking for her husband, George Fowler. Shaken, the Flame takes the girl home and when the youth returns he is informed that the Flame is dead. Forlorn, the boy decides to break the bank but the saloon's proprietor plans to rob him instead, and only the Flame's appearance with her six guns saves his life. Not having the courage to tell the boy about his wife and child, the Flame takes her lover to the hotel where she battles with her conscience. Her better nature finally wins, however, and the Flame discovers that there are actually two George Fowlers and that the one she loves is single.